对非String类型进行校验时的出错处理

   我在对User.age (Integer型),进行校验时,如果输入的是字符总是出错:

Failed to convert property value of type [Java.lang.String] to required type [java.lang.Integer] for property age; nested exception is java.lang.NumberFormatException: For input string: "ff"

解决方法:

1.本例用的是commons-validator的开源框架

2.在Controller中加

protected void initBinder(HttpServletRequest request,

       ServletRequestDataBinder binder) {     

              binder.registerCustomEditor(Integer.class, null,new CustomNumberEditor(Integer.class, null, true));

              binder.registerCustomEditor(Long.class, null,new CustomNumberEditor(Long.class, null, true));

              binder.registerCustomEditor(byte[].class,new ByteArrayMultipartFileEditor());

              SimpleDateFormat dateFormat = new SimpleDateFormat(getText("date.format", request.getLocale()));

              dateFormat.setLenient(false);

              binder.registerCustomEditor(Date.class, null,new CustomDateEditor(dateFormat, true));

       }

3.在资源文件ApplicationResources_zh_CN.properties 中加:

 

user.age=\u5e74\u9f84

typeMismatch.java.lang.Integer={0}\u5fc5\u987b\u4e3a\u4e00\u6570\u503c\u3002

4.一些朋友说在用非对象类型如int时也总是出错,但我在测试时发现不管是用int 还是用float,如果不输或输入字符,系统均会自动赋值 int为0,float为0.0